Asked by Nikki
An 825-kg race car can drive around an unbanked turn at a maximum speed of 59 m/s without slipping. The turn has a radius of curvature of 135 m. Air flowing over the car's wing exerts a downward-pointing force (called the downforce) of 2700 N on the car.
a) What is the coefficient of static friction between the track and the car's tires?
b) What would be the maximum speed if no downforce acted on the car?
a) What is the coefficient of static friction between the track and the car's tires?
b) What would be the maximum speed if no downforce acted on the car?
Answers
Answered by
bobpursley
centripetal force=m*v^2/r
normal force=friction=(mg+2700)mu
set normal force = centripetal force
solve for mu.
normal force=friction=(mg+2700)mu
set normal force = centripetal force
solve for mu.
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