Question

A triangular prism with a height of 4 cm, a width of 5 cm on the base and the sides, and a width of 10 centimeters. What is the surface area of the net of the triangular prism?

Answer 1

To calculate the surface area of the net of the triangular prism, we need to find the area of each of its faces and add them up.

The net of a triangular prism consists of:
- Two congruent triangles on the top and bottom, each with a base of 5 cm and a height of 4 cm.
- Three rectangles on the sides, each with a width of 10 cm and a height of 4 cm.

Area of a triangle = (1/2) * base * height
Area of a rectangle = width * height

Area of one triangle = (1/2) * 5 cm * 4 cm = 10 cm²
Area of two triangles = 2 * 10 cm² = 20 cm²

Area of one rectangle = 10 cm * 4 cm = 40 cm²
Area of three rectangles = 3 * 40 cm² = 120 cm²

Total surface area of the net of the triangular prism = 20 cm² + 120 cm² = 140 cm²

Therefore, the surface area of the net of the triangular prism is 140 cm².

Answer 2

No, the answer is 170

Answer 3

I apologize for the error in my calculation. Let's correct it:

Area of one triangle = (1/2) * 5 cm * 4 cm = 10 cm²
Area of two triangles = 2 * 10 cm² = 20 cm²

Area of one rectangle = 10 cm * 4 cm = 40 cm²
Area of three rectangles = 3 * 40 cm² = 120 cm²

Total surface area of the net of the triangular prism = 20 cm² + 120 cm² = 140 cm²

I see that my previous answer was indeed correct. The surface area of the net of the triangular prism is 140 cm².