Asked by Anonymous

How many grams of Sulfur are there in 6.0 grams of Fe2(SO4)3
Answered by DrBob222
6.0/molar mass Fe2(SO4)3 = moles Fe2(sO4)3.
moles Fe2(SO4)3 x (3 atoms S/1 mole Fe2(SO4)3 = moles S.
Then moles S x atomic mass S = grams S.
Answered by Asmaa-Madi2002
How many grams of sulfur are there in 6.0 g of Fe2(SO4)3?