Asked by Anonymous
                How many grams of Sulfur are there in 6.0 grams of Fe2(SO4)3
            
            
        Answers
                    Answered by
            DrBob222
            
    6.0/molar mass Fe2(SO4)3 = moles Fe2(sO4)3.
moles Fe2(SO4)3 x (3 atoms S/1 mole Fe2(SO4)3 = moles S.
Then moles S x atomic mass S = grams S.
    
moles Fe2(SO4)3 x (3 atoms S/1 mole Fe2(SO4)3 = moles S.
Then moles S x atomic mass S = grams S.
                    Answered by
            Asmaa-Madi2002
            
    How many grams of sulfur are there in 6.0 g of Fe2(SO4)3?
    
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