2y^2-y(3-2(y-4)-y)
Get rid of the inner brackets:
2y^2 - y(3 - 2y + 8 -y)
Multiply the y into the brackets:
2y^2 - (3y - 2y^2 + 8y - y^2)
2y^2 - 3y + 2y^2 - 8y + y^2
Now collect the terms together.
The problem is simplify:
2y^2-y[3-2(y-4)-y]
how did he get that answer?
Get rid of the inner brackets:
2y^2 - y(3 - 2y + 8 -y)
Multiply the y into the brackets:
2y^2 - (3y - 2y^2 + 8y - y^2)
2y^2 - 3y + 2y^2 - 8y + y^2
Now collect the terms together.
Let's break it down step by step:
Step 1: Simplify the expression inside the square brackets [ ]:
Inside the square brackets [ ], there is a subtraction operation (3 - 2(y - 4) - y).
To simplify this, apply the distributive property by multiplying -2 to both y and -4:
3 - 2y + 8 - y
Combine like terms:
(3 + 8) - (2y + y)
11 - 3y
Step 2: Expand the expression by distributing y in front of the square brackets [ ]:
2y^2 - y(11 - 3y)
Apply the distributive property again:
2y^2 - 11y + 3y^2
Step 3: Combine like terms:
2y^2 + 3y^2 - 11y
Step 4: Simplify further:
5y^2 - 11y
So the final answer is 5y^2 - 11y.