Triangle ABC has vertices point A(−2,−2) , point B(−4,−3) , and point C(−2,−5) . Find the coordinates of A′ , B′ , and C′ after a dilation with a scale factor of 3 and a center point of dilation at the origin

Answer 1

To find the coordinates of the vertices after a dilation with a scale factor of 3 and a center point at the origin, we can use the following formula:

A′ = (3 * x, 3 * y)

Let's calculate the new coordinates for each point:

For point A(-2, -2):
A′ = (3 * (-2), 3 * (-2))
A′ = (-6, -6)

So, A′ is located at (-6, -6).

For point B(-4, -3):
B′ = (3 * (-4), 3 * (-3))
B′ = (-12, -9)

So, B′ is located at (-12, -9).

For point C(-2, -5):
C′ = (3 * (-2), 3 * (-5))
C′ = (-6, -15)

So, C′ is located at (-6, -15).

Therefore, the coordinates of A', B', and C' after the dilation with a scale factor of 3 and a center point of dilation at the origin are:
A′(-6, -6), B′(-12, -9), C′(-6, -15).