Question

derive 2ln(3x^2+5x)

Answer 1

To derive the function 2ln(3x^2 + 5x), we can use the chain rule.

Let u = 3x^2 + 5x
Then, du = (6x + 5)dx

Now, derive 2ln(u):
d(2ln(u)) = 2 * 1/u * du
d(2ln(u)) = 2 * 1/(3x^2 + 5x) * (6x + 5)dx
d(2ln(u)) = 2(6x + 5)/(3x^2 + 5x)

Therefore, the derivative of 2ln(3x^2 + 5x) is:
2(6x + 5)/(3x^2 + 5x)