Asked by Sasha

When will your apparent weight be greatest, as measured by a a scale in a moving elevator; when the elevators: (a) accel. downward (b) accel. upward (c) is in free fall (d) moves upward at a constant speed? In what case would you weight be the least? When would it be the same as when you are on the ground?

Answers

Answered by bobpursley
Think about it.

weightapparent=mg+ma where a is up. What if a is down? What if a=-g?
Answered by MathMate
Apparent weight
= m(g+a)
where g=9.8 m/s²
a=acceleration, positive upwards.
(a) W=m(g-|a|)
(b) W=m(g+|a|)
(c) W=m(g-|g|) = 0
(d) W=m(g+|0|) = mg
Answered by Sasha
so the it would be the least on the way down, b/c your force, pushing on the scale is less. And it is greatest on the way up, since your force of push is stronger. And I would say in free fall it is the same as ground state?
Answered by MathMate
Rethink free-fall.
Answered by Sasha
ohh okay so the weight would be the same on the ground if its moving up at a constant speed?
Answered by MathMate
Exactly. When it moves upwards (or downwards) at a uniform velocity, the reaction on the floor is the same as the weight. You have probably experienced this when you ride on an elevator.
Answered by Sasha
sweet!! thank you =)
Answered by MathMate
You're welcome!
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