Asked by Sasha
When will your apparent weight be greatest, as measured by a a scale in a moving elevator; when the elevators: (a) accel. downward (b) accel. upward (c) is in free fall (d) moves upward at a constant speed? In what case would you weight be the least? When would it be the same as when you are on the ground?
Answers
Answered by
bobpursley
Think about it.
weightapparent=mg+ma where a is up. What if a is down? What if a=-g?
weightapparent=mg+ma where a is up. What if a is down? What if a=-g?
Answered by
MathMate
Apparent weight
= m(g+a)
where g=9.8 m/s²
a=acceleration, positive upwards.
(a) W=m(g-|a|)
(b) W=m(g+|a|)
(c) W=m(g-|g|) = 0
(d) W=m(g+|0|) = mg
= m(g+a)
where g=9.8 m/s²
a=acceleration, positive upwards.
(a) W=m(g-|a|)
(b) W=m(g+|a|)
(c) W=m(g-|g|) = 0
(d) W=m(g+|0|) = mg
Answered by
Sasha
so the it would be the least on the way down, b/c your force, pushing on the scale is less. And it is greatest on the way up, since your force of push is stronger. And I would say in free fall it is the same as ground state?
Answered by
MathMate
Rethink free-fall.
Answered by
Sasha
ohh okay so the weight would be the same on the ground if its moving up at a constant speed?
Answered by
MathMate
Exactly. When it moves upwards (or downwards) at a uniform velocity, the reaction on the floor is the same as the weight. You have probably experienced this when you ride on an elevator.
Answered by
Sasha
sweet!! thank you =)
Answered by
MathMate
You're welcome!
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