Asked by rasuka_geo

In a ferris wheel, one person is at the top and another at the bttom. The ferris wheel rotates such that the magnitude of the tangetial velocity of each person is equal |v|top=|v|bottom. Determine for the person at the bottom, the force the seat exerts on the person. Use a standard man mass of 70kg and the speed of the ferris wheel with 2.3 revolutions per minute and R=16.1m
I don't even know where to begin to attempt this problem!
Answered by bobpursley
force on the bottom: mg+ mv^2/r
Answered by Anonymous
is g gravity (9.81)?
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