Question

A water slide is constructed so that swimmers, starting from rest at the top of the slide, leave the end of the slide traveling horizontally.

One person hits the water 5.00 m from the end of the slide in a time of 1.000 s after leaving the slide.

Ignoring friction and air resistance, find the height H in the drawing.

meters?
P.S. (i tried to use h=ut + 1/2at^2)

Answer 1

Time, t = 1 s.
Vertical velocity, u = 0
H = ut+ (1/2)gt²
=0*1 -(1/2)(9.8)*1²
=-4.9 m

Note: the distance 5 m is not used. When the initial velocity of 5 m/s does not hvae a vertical component, the initial velocity does not affect the outcome.

Answer 2

Well, your answer is partially right so it's wrong.
The right answer is:

H = h1 + h2 = [ut + (1/2)gt^2] + [(1/2)v^2/g] = (0*1 + (1/2)*9.81*1^2) + [(1/2)*(5.00m/1s)^2 / 9.81) = 6.17m