Question
how is the domain [3/2,oo) in sqrt 2a-3
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GPT 3.5
To determine the domain of the function sqrt(2a-3) where a is the variable, we need to find the values of a for which the function is defined.
The function sqrt(2a-3) is defined for values of a such that the expression under the square root is non-negative. In other words, 2a-3 must be greater than or equal to 0:
2a - 3 >= 0
2a >= 3
a >= 3/2
Therefore, the domain of sqrt(2a-3) is all real numbers greater than or equal to 3/2 (3/2, ∞). The interval [3/2, ∞) is equivalent to [3/2, ∞) in interval notation.
The function sqrt(2a-3) is defined for values of a such that the expression under the square root is non-negative. In other words, 2a-3 must be greater than or equal to 0:
2a - 3 >= 0
2a >= 3
a >= 3/2
Therefore, the domain of sqrt(2a-3) is all real numbers greater than or equal to 3/2 (3/2, ∞). The interval [3/2, ∞) is equivalent to [3/2, ∞) in interval notation.