Asked by Anonymous
The measure of one of the equal angles in an isosceles triangle is twice the measure of the remaining angle. Determine the exact radian measures of the three angles in the triangle.
Answers
Answered by
MathMate
Let each of the equal angles be A.
Since we know that the angles of a triangle add up to 180°, we determine that the third angle is (180-2A)°.
Thus
A=2(180-2A)
5A = 360
A = 72
Therefore the angles are 72°, 72° and 36°.
Since we know that the angles of a triangle add up to 180°, we determine that the third angle is (180-2A)°.
Thus
A=2(180-2A)
5A = 360
A = 72
Therefore the angles are 72°, 72° and 36°.
Answered by
Anonymous
Let x represent the 3rd angle
Thus 2x represents the other 2 angles
We know that a triangle totals 180 degress
180 = x + 2(2x)
180 = 5x
x = 36 degrees
2x
2(36) = 72 degrees
Convert to radians using the pi/180 formula
Therefore the angles are pi/5, 2pi/5, 2pi/5
Thus 2x represents the other 2 angles
We know that a triangle totals 180 degress
180 = x + 2(2x)
180 = 5x
x = 36 degrees
2x
2(36) = 72 degrees
Convert to radians using the pi/180 formula
Therefore the angles are pi/5, 2pi/5, 2pi/5
There are no AI answers yet. The ability to request AI answers is coming soon!