23pi/6 is pi/6 short of two rotations of 4pi
so 23pi/6 is coterminal with -pi/6
(23pi/6 = 690º. 690º - 360º = 330 or -30º)
sec (23pi/6) = sec (-pi/6)
= 1/cos(-pi/6)
= 1/cos(pi/6)
= 1/(√3/2)
= 2/√3 or 2√3/2 after rationalizing the denominator
How do you figure out the exact circular function value of sec(23pie/6)?
*I don't know how to get the [pie]symbol on my keyboard
1 answer