True
False
True
True
A rectangle has length 9.3×102
cm and width 8.1×10
cm. Which of these statements are true?(4 points)
True False
The area of the rectangle is 7.533×104 cm2
The perimeter of the rectangle is 1.71×103 cm
The length of the rectangle is approximately 1.15×10
times greater than the width
The length of the rectangle squared is approximately 8.65×105
9 answers
so The area of the rectangle is 7.533×10^4 cm^2 is true?
Yes, that statement is true. The area of the rectangle can be calculated by multiplying the length by the width:
Area = 9.3×10^2 cm * 8.1×10 cm
Area = 75.33×10^2 cm^2
Area = 7.533×10^4 cm^2
So, the area of the rectangle is 7.533×10^4 cm^2.
Area = 9.3×10^2 cm * 8.1×10 cm
Area = 75.33×10^2 cm^2
Area = 7.533×10^4 cm^2
So, the area of the rectangle is 7.533×10^4 cm^2.
what about The perimeter of the rectangle is 1.71×10^3 cm
Let's calculate the perimeter of the rectangle:
Perimeter = 2*(length + width)
Perimeter = 2*(9.3×10^2 cm + 8.1×10 cm)
Perimeter = 2*(9.3×10^2 cm + 8.1×10 cm)
Perimeter = 2*(9.3×10^2 cm + 8.1×10 cm)
Perimeter = 2*(936 cm + 81 cm)
Perimeter = 2*(1017 cm)
Perimeter = 2034 cm
The perimeter of the rectangle is not 1.71×10^3 cm, it is actually 2034 cm. Therefore, the statement "The perimeter of the rectangle is 1.71×10^3 cm" is false.
Perimeter = 2*(length + width)
Perimeter = 2*(9.3×10^2 cm + 8.1×10 cm)
Perimeter = 2*(9.3×10^2 cm + 8.1×10 cm)
Perimeter = 2*(9.3×10^2 cm + 8.1×10 cm)
Perimeter = 2*(936 cm + 81 cm)
Perimeter = 2*(1017 cm)
Perimeter = 2034 cm
The perimeter of the rectangle is not 1.71×10^3 cm, it is actually 2034 cm. Therefore, the statement "The perimeter of the rectangle is 1.71×10^3 cm" is false.
what about
The length of the rectangle is approximately 1.15×10
times greater than the width
The length of the rectangle is approximately 1.15×10
times greater than the width
Let's compare the length and width of the rectangle to see if the statement is true.
Length = 9.3×10^2 cm
Width = 8.1×10 cm
To determine if the length is approximately 1.15 times greater than the width, we need to compare the two values:
9.3×10^2 / 8.1×10 ≈ 1.148148148
Since 1.15 is close to 1.148148148, we can say that the statement is true. The length of the rectangle is approximately 1.15 times greater than the width.
Length = 9.3×10^2 cm
Width = 8.1×10 cm
To determine if the length is approximately 1.15 times greater than the width, we need to compare the two values:
9.3×10^2 / 8.1×10 ≈ 1.148148148
Since 1.15 is close to 1.148148148, we can say that the statement is true. The length of the rectangle is approximately 1.15 times greater than the width.
and
The length of the rectangle squared is approximately 8.65×10^5
The length of the rectangle squared is approximately 8.65×10^5
Let's find the square of the length of the rectangle and check if it is approximately 8.65×10^5.
Length = 9.3×10^2 cm
Length^2 = (9.3×10^2)^2
Length^2 = 9.3^2 * (10^2)^2
Length^2 = 86.49 * 10^4
Length^2 = 8.649 × 10^5
Therefore, the statement "The length of the rectangle squared is approximately 8.65×10^5" is true.
Length = 9.3×10^2 cm
Length^2 = (9.3×10^2)^2
Length^2 = 9.3^2 * (10^2)^2
Length^2 = 86.49 * 10^4
Length^2 = 8.649 × 10^5
Therefore, the statement "The length of the rectangle squared is approximately 8.65×10^5" is true.
1 answer