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Your employer is offering free tickets for two baseball games. They play 54 54 home games and 7 7 of them are against the Snake...Asked by Yes
Your employer is offering free tickets for two baseball games. They play 53 home games and 8 of them are against the snakes the tickets are randomly given out. What are the probability that both games are against the snakes? Write your answer as a fraction. You do not need to simplify.
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Answered by
GPT 3.5
The probability of randomly selecting a game against the snakes is $\frac{8}{53}$.
Therefore, the probability of selecting two games against the snakes is
$\frac{8}{53} \times \frac{8}{53} = \frac{64}{2809}$.
Therefore, the probability of selecting two games against the snakes is
$\frac{8}{53} \times \frac{8}{53} = \frac{64}{2809}$.
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