Question

how to work out partial fraction decomposition when given
1/x(x^2+1) and 2x-1/(x+4)(x-3)

if you could give me an idea of the formula and what changes i need to make to the formula when the denominator changes that would help and please use idiot speak because the text books are confusing me

i think i worked out the second one but i still cant do the first

is it = 9/7(x+4)+5/7(x-3)???

Answer 1

let 1/x(x^2+1)
= A/x + (Bx+C)/(x^2+1)
= [A(x^2+1) + x(Bx+C)]/[x(x^2+1)]
= [Ax^2 + A + Bx^2 + Cx}/[x(x^2+1)]
= [x^2(A+B) + Cx + A]/[x(x^2+1)]

there is no x term in the original numerator, so C = 0
there is no x^2 in the original numerator, so A+B = 0,
The constant was 1, so A = 1
then B = -1, since A+B=0

so 1/x(x^2+1)
= 1/x -x/(x^2 + 1)

Answer 2

careful how you write the second,
it should be

9/(7(x+4))+5/(7(x-3))

Answer 3

What happened to the grocer who stacked all of the liquid detergent no the high shelf ?