The formula for finding the area of a triangle is:
\[ A = \frac{1}{2} \times base \times height \]
Where:
A = Area of the triangle
base = length of the base of the triangle
height = height of the triangle from the base to the opposite vertex
What is the formula ohh they triangle area
7 answers
Triangle has the base of three in the height of four what is the area
Using the formula for finding the area of a triangle, given that the base is 3 and the height is 4:
\[ A = \frac{1}{2} \times base \times height \]
Substitute the values of the base and height into the formula:
\[ A = \frac{1}{2} \times 3 \times 4 \]
\[ A = \frac{1}{2} \times 12 \]
\[ A = 6 \]
Therefore, the area of the triangle with a base of 3 and a height of 4 is 6 square units.
\[ A = \frac{1}{2} \times base \times height \]
Substitute the values of the base and height into the formula:
\[ A = \frac{1}{2} \times 3 \times 4 \]
\[ A = \frac{1}{2} \times 12 \]
\[ A = 6 \]
Therefore, the area of the triangle with a base of 3 and a height of 4 is 6 square units.
5
If the base of the triangle is 3 units and the height is 4 units, the area would actually be:
\[ A = \frac{1}{2} \times base \times height \]
\[ A = \frac{1}{2} \times 3 \times 4 \]
\[ A = \frac{1}{2} \times 12 \]
\[ A = 6 \]
Therefore, the area of the triangle with a base of 3 units and a height of 4 units is indeed 6 square units.
\[ A = \frac{1}{2} \times base \times height \]
\[ A = \frac{1}{2} \times 3 \times 4 \]
\[ A = \frac{1}{2} \times 12 \]
\[ A = 6 \]
Therefore, the area of the triangle with a base of 3 units and a height of 4 units is indeed 6 square units.
A right triangle
If it's a right triangle, you can also use the Pythagorean Theorem in conjunction with the formula for the area of a triangle.
Given that the base is 3 units and the height is 4 units in a right triangle, the hypotenuse can be calculated using the Pythagorean Theorem:
\[ c^2 = a^2 + b^2 \]
where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.
In this case, the base (a) is 3 units, the height (b) is 4 units, and the hypotenuse (c) is:
\[ c^2 = 3^2 + 4^2 \]
\[ c^2 = 9 + 16 \]
\[ c^2 = 25 \]
\[ c = 5 \]
So, the length of the hypotenuse is 5 units. Now, you can calculate the area of the right triangle using the formula:
\[ A = \frac{1}{2} \times base \times height \]
\[ A = \frac{1}{2} \times 3 \times 4 \]
\[ A = \frac{1}{2} \times 12 \]
\[ A = 6 \]
Therefore, the area of the right triangle with a base of 3 units and a height of 4 units is 6 square units.
Given that the base is 3 units and the height is 4 units in a right triangle, the hypotenuse can be calculated using the Pythagorean Theorem:
\[ c^2 = a^2 + b^2 \]
where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.
In this case, the base (a) is 3 units, the height (b) is 4 units, and the hypotenuse (c) is:
\[ c^2 = 3^2 + 4^2 \]
\[ c^2 = 9 + 16 \]
\[ c^2 = 25 \]
\[ c = 5 \]
So, the length of the hypotenuse is 5 units. Now, you can calculate the area of the right triangle using the formula:
\[ A = \frac{1}{2} \times base \times height \]
\[ A = \frac{1}{2} \times 3 \times 4 \]
\[ A = \frac{1}{2} \times 12 \]
\[ A = 6 \]
Therefore, the area of the right triangle with a base of 3 units and a height of 4 units is 6 square units.
1 answer