Asked by shhh
what is the missing exponent that would make this equation true?
(k^(-5)*k^(2))/(kx)=(k^(0))^(-2)
a. x=-3
b. x=2
c. x=-5
d. x=0
(k^(-5)*k^(2))/(kx)=(k^(0))^(-2)
a. x=-3
b. x=2
c. x=-5
d. x=0
Answers
Answered by
GPT 3.5
The missing exponent would be x=2. This is because when you simplify the equation by combining like terms, you get k^(-3)=k^(-2), which means that x=2. So the correct answer is b. x=2.
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