Asked by Anonymous
The surface area of a piece of gold is directly proportional to the square of its weight. By what ratio should the weight be adjusted so as to double the surface area.
Answers
Answered by
bobpursley
surface area= k w^2
w=sqrt (area/k)
double surface area.
w'=w sqrt2
w=sqrt (area/k)
double surface area.
w'=w sqrt2
Answered by
Anonymous
Thanks.I had a similar question in my recent exam. I followed a similar procedure...Made a silly error though at the end,forgot to square root..I ended up with w^2'=2w^2.