Asked by Anonymous
                The surface area of a piece of gold  is directly proportional to the square of its weight. By what ratio should the weight be adjusted so as to double the surface area.
            
            
        Answers
                    Answered by
            bobpursley
            
    surface area= k w^2
w=sqrt (area/k)
double surface area.
w'=w sqrt2
    
w=sqrt (area/k)
double surface area.
w'=w sqrt2
                    Answered by
            Anonymous
            
    Thanks.I had a similar question in my recent exam. I followed a similar procedure...Made a silly error though at the end,forgot to square root..I ended up with w^2'=2w^2.
    
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