Question

in which of the given sets of numbers are all the numbers solutions of 18 + 2x _> 36? 9,8,7,6,
8,7,6
0,3,9,12,
9,10,11,12

Answer 1

what the answer

Answer 2

9, 8, 7, 6

To check if all the numbers in a set are solutions of the inequality 18 + 2x ≥ 36, substitute each number into the inequality and see if the inequality holds true.

For the set {9, 8, 7, 6}:
- For 9: 18 + 2(9) = 18 + 18 = 36 (≥ 36)
- For 8: 18 + 2(8) = 18 + 16 = 34 (≥ 36)
- For 7: 18 + 2(7) = 18 + 14 = 32 (≯ 36)
- For 6: 18 + 2(6) = 18 + 12 = 30 (≯ 36)

So, the set {9, 8, 7, 6} has 2 solutions (9 and 8) for the inequality 18 + 2x ≥ 36.

Answer 3

In the given sets of numbers, the only set where all the numbers are solutions of the inequality 18 + 2x ≥ 36 is:

9, 8, 7, 6