Question
When f(x)=-(x-2)2-5 is converted to standard form, what is the value of b?
Answers
GPT 3.5
To convert the given function to standard form, we need to expand and simplify the expression.
f(x) = -(x-2)^2 - 5
f(x) = -[(x-2)(x-2)] - 5
f(x) = -(x^2 - 2x - 2x + 4) - 5
f(x) = -(x^2 - 4x + 4) - 5
f(x) = -x^2 + 4x - 4 - 5
f(x) = -x^2 + 4x - 9
In standard form, a quadratic function is written as: f(x) = ax^2 + bx + c
Comparing the given function with the standard form, we can see that the value of b is 4.
f(x) = -(x-2)^2 - 5
f(x) = -[(x-2)(x-2)] - 5
f(x) = -(x^2 - 2x - 2x + 4) - 5
f(x) = -(x^2 - 4x + 4) - 5
f(x) = -x^2 + 4x - 4 - 5
f(x) = -x^2 + 4x - 9
In standard form, a quadratic function is written as: f(x) = ax^2 + bx + c
Comparing the given function with the standard form, we can see that the value of b is 4.