Use the table to answer the question. y 3y−1=x (x,f(x)) −2 −0.89 (−0.89,−2) −1 −0.67 (−0.67,−1) 0 −1 (−1,B) 1 2 (2,1) 2 A (A,2) 3 26 (26,3) In order to graph a logarithmic function, a table has been created. The function has been rewritten in exponential form. What are the values for A and B ?

To convert the function y = 3y - 1 = x to exponential form, we can rewrite it as:

3^y-1 = x

Looking at the table, we can see that when x = 0, y = -1. This means that:

3^(-1) = 0

Which is not possible, as any number raised to a negative exponent is always a fraction. Therefore, the value of B is undefined.

Similarly, looking at the table when x = 2, y = A. This means:

3^A - 1 = 2

Therefore, A can be calculated as follows:

3^A = 2 + 1
3^A = 3
A = 1

So, the values for A and B are A = 1 and B = undefined.