Asked by Z32

[Mean Value Theorem]

f(x)=-3x^3 - 4x^2 - 2x -3 on the closed interval [0,8].

Find the smallest value of c that satisfies the conclusion of the Mean Value Theorem for this function defined on the given interval.

I got 8 - sqrt(5696) / -18 = 3.748436059 but it's not right.
Answered by Z32
I redid my math and I think I did my calculations wrong. I got 8 +- sqrt(8000)/ -18 but it's still wrong.
Answered by Z32
Nevermind, I had an error in my calculations. It was sqrt(8128). I got the answer.
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