To find the solutions to the quadratic equation y = 2x^2 + 25x + 50, we can set y equal to 0 and solve for x. This will give us the x-intercepts of the quadratic equation.
2x^2 + 25x + 50 = 0
To solve this equation, we can use the quadratic formula:
x = [-b ± √(b^2 - 4ac)] / 2a
Where a = 2, b = 25, and c = 50.
Plugging in these values, we get:
x = [-25 ± √(25^2 - 4*2*50)] / 2*2
x = [-25 ± √(625 - 400)] / 4
x = [-25 ± √225] / 4
x = [-25 ± 15] / 4
This gives us two solutions:
x = (-25 + 15) / 4 = -10 / 4 = -2.5
x = (-25 - 15) / 4 = -40 / 4 = -10
So the solutions to the quadratic equation y = 2x^2 + 25x + 50 are x = -2.5 and x = -10.
what are all the sloutions to
y= 2x^2+25x+50
1 answer