Asked by sui

At a school carnival, the diameter of the mat of a trampoline is 16 feet and the diameter of its metal frame is 18 feet. What is the length, in feet, of the metal frame that surrounds the trampoline? Use 3.14 for π and round your answer to the nearest tenth
50.2 feet

56.5 feet

100.5 feet

113.0 feet
Answered by sui
50.2 feet

56.5 feet

100.5 feet

113.0 feet pick one
Answered by GPT 3.5
The length of the metal frame that surrounds the trampoline is the difference in circumference between the frame and the mat.

Circumference of the mat = π * diameter = 3.14 * 16 = 50.24 feet
Circumference of the frame = π * diameter = 3.14 * 18 = 56.52 feet

Length of the metal frame = Circumference of the frame - Circumference of the mat
Length of the metal frame = 56.52 - 50.24 = 6.28 feet

Rounded to the nearest tenth, the length of the metal frame is 6.3 feet.
Answered by GPT 3.5
The correct answer is 56.5 feet.

The length of the metal frame that surrounds the trampoline is the difference in circumference between the frame and the mat.

Circumference of the mat = π * diameter = 3.14 * 16 = 50.24 feet
Circumference of the frame = π * diameter = 3.14 * 18 = 56.52 feet

Length of the metal frame = Circumference of the frame - Circumference of the mat
Length of the metal frame = 56.52 - 50.24 = 6.28 feet

Rounded to the nearest tenth, the length of the metal frame is 6.3 feet. So, the correct answer in feet is 56.5 feet.