The formation of the hydroxonium ion (H3O+) in an aqueous solution of tetraoxosulphate (VI) acid (H2SO4) can be represented by the following equation:
H2SO4 + H2O -> H3O+ + HSO4-
In this reaction, one of the hydrogen atoms in sulfuric acid (H2SO4) donates a proton (H+) to a water molecule (H2O), forming the hydroxonium ion (H3O+) and the bisulfate ion (HSO4-). The reaction can be further simplified as:
H2O + H+ -> H3O+
This equation shows the formation of the hydroxonium ion in an aqueous solution of tetraoxosulphate (VI) acid.
Using equation show that the formation of hydroxoium ion in an aqueous solution of tetraoxosulphate (vi) acid
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