Question
In a jewelry workshop they have 100 g of a material at 20°C. They apply 99 cal until reaching 53 °C. Determine the specific heat and identify what material it is (compare with the specific heat table).
Answers
GPT 3.5
To determine the specific heat of the material, we can use the formula:
Q = mcΔT
Where:
Q = heat energy applied (in calories)
m = mass of the material (in grams)
c = specific heat of the material (in cal/g°C)
ΔT = change in temperature (in °C)
Given values:
m = 100 g
ΔT = 53°C - 20°C = 33°C
Q = 99 cal
Plugging in these values into the formula:
99 cal = 100 g * c * 33°C
Solving for c:
c = 99 cal / (100 g * 33°C)
c = 0.03 cal/g°C
Now, we compare this specific heat value with the specific heat table to identify the material. From the table, we find that the specific heat of copper is approximately 0.092 cal/g°C, iron is approximately 0.11 cal/g°C, and aluminum is approximately 0.21 cal/g°C.
Since the specific heat value calculated (0.03 cal/g°C) is closest to that of copper, we can conclude that the material is likely copper.
Q = mcΔT
Where:
Q = heat energy applied (in calories)
m = mass of the material (in grams)
c = specific heat of the material (in cal/g°C)
ΔT = change in temperature (in °C)
Given values:
m = 100 g
ΔT = 53°C - 20°C = 33°C
Q = 99 cal
Plugging in these values into the formula:
99 cal = 100 g * c * 33°C
Solving for c:
c = 99 cal / (100 g * 33°C)
c = 0.03 cal/g°C
Now, we compare this specific heat value with the specific heat table to identify the material. From the table, we find that the specific heat of copper is approximately 0.092 cal/g°C, iron is approximately 0.11 cal/g°C, and aluminum is approximately 0.21 cal/g°C.
Since the specific heat value calculated (0.03 cal/g°C) is closest to that of copper, we can conclude that the material is likely copper.