The correct answer is:
a. x = 3
Explanation:
(k^5 * k^2) / (k^x) = k^(5 + 2) / k^(x) = k^7 / k^x = k^(7 - x)
(k^2)^(-2) = k^(2 * -2) = k^(-4)
Now, we need to set the two expressions equal to each other:
k^(7 - x) = k^(-4)
7 - x = -4
x = 7 + 4
x = 3
Therefore, the missing exponent that would make this equation true is x = 3.
what is the missing exponent that would make this equation true?
(k^(5)*k^(2))/(k^(x))=(k^(2))^(-2)
a. x=3
b. x=11
c. x=9
d. x=0
e. x=1
f. x=6
1 answer