Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup.(1 point)

Question

Responses

92+16x=104+13x ; x=6
92 plus 16 x equals 104 plus 13 x ; x equals 6

92−16x=104−13x ; x=−4
92 minus 16 x equals 104 minus 13 x ; x equals negative 4

104+16x=92+13x ; x=4
104 plus 16 x equals 92 plus 13 x ; x equals 4

92+16x=104+13x ; x=4
92 plus 16 x equals 104 plus 13 x ; x equals 4

Answer 1

The correct equation would be: 92 + 16x = 104 + 13x, where x is the number of minutes.

Solving for x:
92 + 16x = 104 + 13x
16x - 13x = 104 - 92
3x = 12
x = 4

So, the two machines will have filled the same number of cans of soup after 4 minutes.

Therefore, the correct response is:
92+16x=104+13x ; x=4
92 plus 16 x equals 104 plus 13 x ; x equals 4