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Change the equation from standard form to slope-intercept form by solving for y. 11x - 8y = -48 Bob: Subtract 11x from both sid...Asked by 000000
Change the equation from standard form to slope-intercept form by solving for y.
11x - 8y = -48
Bob:
Subtract 11x from both sides: -8y = -59x
Divide by -8 on both sides: y = 7.375
Bill:
Subtract 11x from both sides: -8y = -11x - 48
Divide by -8 on both sides: y = 11/8 x + 6
Bud:
Subtract 11x from both sides: -8y = -11x - 48
Divide by -8 on both sides: y = -11x + 6
Who is correct?
Responses
Bob
Bob
Bill
Bill
Bud
Bud
All of them are correct
11x - 8y = -48
Bob:
Subtract 11x from both sides: -8y = -59x
Divide by -8 on both sides: y = 7.375
Bill:
Subtract 11x from both sides: -8y = -11x - 48
Divide by -8 on both sides: y = 11/8 x + 6
Bud:
Subtract 11x from both sides: -8y = -11x - 48
Divide by -8 on both sides: y = -11x + 6
Who is correct?
Responses
Bob
Bob
Bill
Bill
Bud
Bud
All of them are correct
Answers
Answered by
000000
what?
Answered by
GPT 3.5
.
Answered by
GPT 3.5
I apologize for the confusion. Let's reevaluate the solutions provided by Bob, Bill, and Bud for changing the equation from standard form to slope-intercept form:
Given equation: 11x - 8y = -48
Bob's solution:
-8y = -11x + 48
Dividing by -8 on both sides:
y = 11/8x + 6
Bill's solution:
-8y = -11x + 48
Dividing by -8 on both sides:
y = 11/8x + 6
Bud's solution:
-8y = -11x + 48
Dividing by -8 on both sides:
y = 11/8x + 6
Upon review, it appears that all three solutions are identical, with the correct form being y = 11/8x + 6. Therefore, all of them are correct. Thank you for your patience.
Given equation: 11x - 8y = -48
Bob's solution:
-8y = -11x + 48
Dividing by -8 on both sides:
y = 11/8x + 6
Bill's solution:
-8y = -11x + 48
Dividing by -8 on both sides:
y = 11/8x + 6
Bud's solution:
-8y = -11x + 48
Dividing by -8 on both sides:
y = 11/8x + 6
Upon review, it appears that all three solutions are identical, with the correct form being y = 11/8x + 6. Therefore, all of them are correct. Thank you for your patience.