The correct response is (6.3×10^9) + (4.3×10^11) = 4.363×10^11.
Therefore, the total kilowatt-hours of electricity used during these two years is 4.363×10^11 kilowatt-hours.
The use of electricity in the US in 1902 was 6.03 x 10^9 kilowatt-hours. The use of electricity in the US in 1950 was 4.3 x 10^11 kilowatt-hours. What was the total kilowatt-hours of electricity used during these two years? (2 points) Responses (6.3×109)+(4.3×1011)=10.33×1020=1.033×1019 open paren 6 point 3 times 10 to the 9th power close paren plus open paren 4 point 3 times 10 to the 11th power close paren is equal to 10 point 3 3 times 10 to the 20th power is equal to 1 point 0 3 3 times 10 to the 19th power (6.3×109)+(4.3×1011)=0.063×1011+(4.3×1011)=4.363×1011 open paren 6 point 3 times 10 to the 9th power close paren plus open paren 4 point 3 times 10 to the 11th power close paren is equal to 0 point 0 6 3 times 10 to the 11th power plus open paren 4 point 3 times 10 to the 11th power close paren is equal to 4 point 3 6 3 times 10 to the 11th power (6.3×109)×(4.3×1011)=25.929×102=2.6×101 open paren 6 point 3 times 10 to the 9th power close paren times open paren 4 point 3 times 10 to the 11th power close paren is equal to 25 point 9 2 9 times 10 squared is equal to 2 point 6 times 10 to the 1th power (6.3×109)×(4.3×1011)=25.929×1020=2.6×1019 open paren 6 point 3 times 10 to the 9th power close paren times open paren 4 point 3 times 10 to the 11th power close paren is equal to 25 point 9 2 9 times 10 to the 20th power is equal to 2 point 6 times 10 to the 19th power
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so it would be the answer: (6.3 * 10^9) + (4.3 * 10^11) = 0.063 * 10^11 + (4.3 * 10^11) = 4.363 * 10^11?
Yes, that is correct. The total kilowatt-hours of electricity used during the two years is 4.363 * 10^11 kilowatt-hours.
The use of electricity in the US in 1902 was 6.03 x 10^9 kilowatt-hours. The use of electricity in the US in 1950 was 4.3 x 10^11 kilowatt-hours. how many times more was the electricity used in 1950 than 1902? express your answer in scientific notation.
To find out how many times more electricity was used in 1950 than in 1902, we divide the electricity used in 1950 by the electricity used in 1902:
(4.3 * 10^11) / (6.03 * 10^9)
Dividing the values, we get:
(4.3 / 6.03) * 10^(11-9)
= 0.712871287 * 10^2
= 7.1287 * 10^1
= 71.287
Therefore, the electricity used in 1950 was 71.287 times more than in 1902, expressed in scientific notation as 7.1287 * 10^1.
(4.3 * 10^11) / (6.03 * 10^9)
Dividing the values, we get:
(4.3 / 6.03) * 10^(11-9)
= 0.712871287 * 10^2
= 7.1287 * 10^1
= 71.287
Therefore, the electricity used in 1950 was 71.287 times more than in 1902, expressed in scientific notation as 7.1287 * 10^1.
1 answer