Use the image to answer the question.

An illustration shows the outline of letter upper T. The vertical rectangular base of the letter has length 12 and width 3. The horizontal rectangular crossbar at the top has thickness 2. The lower sides of the horizontal crossbar on either side of the vertical base measure 4.

What is the area of the polygon? Assume that segments that appear congruent are congruent and angles that appear to be right angles are right angles.

(1 point)
Responses

64 square units
64 square units

52 square units
52 square units

50 square units
50 square units

58 square units

3 answers

The area of the polygon can be found by calculating the area of each individual rectangle and triangle within the shape and then adding them together.

Vertical base rectangle: Length = 12, Width = 3, Area = length x width = 12 x 3 = 36 square units
Horizontal crossbar rectangle: Length = 12, Width = 2, Area = length x width = 12 x 2 = 24 square units
Two triangles on either side of the horizontal crossbar: Base = 12, Height = 4, Area = 0.5 x base x height = 0.5 x 12 x 4 = 24 square units (combined)

Now, add the areas of all these shapes together:
36 (vertical base) + 24 (horizontal crossbar) + 24 (triangles) = 84 square units

Therefore, the area of the polygon is 84 square units.
can you please use one of the following64 square units
64 square units

52 square units
52 square units

50 square units
50 square units

58 square units
Apologies for the error in my previous response. Let's reevaluate the areas and match it with the provided options.

Vertical base rectangle: Length = 12, Width = 3, Area = length x width = 12 x 3 = 36 square units
Horizontal crossbar rectangle: Length = 12, Width = 2, Area = length x width = 12 x 2 = 24 square units
Two triangles on either side of the horizontal crossbar: Base = 12, Height = 4, Area = 0.5 x base x height = 0.5 x 12 x 4 = 24 square units

Now, add the areas of all these shapes together:
36 (vertical base) + 24 (horizontal crossbar) + 24 (triangles) = 84 square units

Since there was an error in my previous response, unfortunately, none of the provided options match the correct area of the polygon.
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