Question

A sample of carbon dioxide gas at a pressure of 1.04 atm and a temperature of 293 °C, occupies a volume of 659 mL. If the gas is cooled at constant pressure until its volume is 557 mL, the temperature of the gas sample will be

Answer 1

245 °C.

Using the combined gas law formula:

P1V1 / T1 = P2V2 / T2

we can plug in the values to find T2:

(1.04 atm)(659 mL) / 293 °C = (1.04 atm)(557 mL) / T2

Solving for T2:

(1.04 atm)(659 mL)(T2) = (1.04 atm)(557 mL)(293 °C)
(1.04)(659 mL) / (1.04)(557 mL) = T2
T2 = 245 °C

Therefore, the temperature of the gas sample will be 245 °C.