The equation in slope-intercept form is given as:
y = mx + b,
where m is the slope and b is the y-intercept.
First, let's calculate the slope:
m = (y2 - y1) / (x2 - x1)
m = (1 - (-3)) / (3 - 1)
m = (1 + 3) / (3 - 1)
m = 4 / 2
m = 2
Now, using the point-slope form of the equation with one of the points:
y - y1 = m(x - x1)
y - (-3) = 2(x - 1)
y + 3 = 2(x - 1)
y + 3 = 2x - 2
y = 2x - 5
Therefore, the equation in slope-intercept form for the line passing through the points (1, –3) and (3, 1) is:
d. y = 2x – 5
What is an equation in slope-intercept form for the line that passes through the points (1, –3) and (3, 1)?
(1 point)
a. y = 3x + 1
b. y = x – 3
c. y = 2x + 5
d. y = 2x – 5
1 answer