Question

y=x²+12x+36

what is the number of solutions

Answers

Answer
y=x²+14x+49
Answer
y=x²+3x-15
Answer
y=x²+x+13
Answer
y=x²+14x+50
Answer
y=x²-10x-23
Answered by GPT 3.5
The given equation y = x² + 12x + 36 can be factored as (x + 6)².

Therefore, the number of solutions for this equation is 1, as the equation has only one root when a perfect square trinomial is factored.
Answered by GPT 3.5
The given equation y = x² + 14x + 49 can be factored as (x + 7)².

Therefore, the number of solutions for this equation is 1, as the equation has only one root when a perfect square trinomial is factored.
Answered by GPT 3.5
To determine the number of solutions for the given equation y = x² + 3x - 15, we can compute the discriminant (Δ) using the quadratic formula Δ = b² - 4ac, where the quadratic equation is in the form ax² + bx + c = 0.

In this case:
a = 1, b = 3, and c = -15

Δ = (3)² - 4*1*(-15)
Δ = 9 + 60
Δ = 69

Since the discriminant (Δ) is positive, there are two distinct real solutions for this quadratic equation.
Answered by GPT 3.5
For the equation y = x² + x + 13, we can calculate the discriminant (Δ) using the quadratic formula, where the equation is in the form ax² + bx + c = 0.

In this case:
a = 1, b = 1, and c = 13

Δ = (1)² - 4*1*13
Δ = 1 - 52
Δ = -51

Since the discriminant (Δ) is negative, the quadratic equation has two complex conjugate solutions.
Answered by GPT 3.5
To determine the number of solutions for the given equation y = x² + 14x + 50, we need to calculate the discriminant (Δ) using the quadratic formula Δ = b² - 4ac, where the quadratic equation is in the form ax² + bx + c = 0.

In this case:
a = 1, b = 14, and c = 50

Δ = (14)² - 4*1*50
Δ = 196 - 200
Δ = -4

Since the discriminant (Δ) is negative, the quadratic equation does not have real solutions. The equation has two complex conjugate solutions that involve imaginary numbers.
Answered by GPT 3.5
For the equation y = x² - 10x - 23, we can calculate the discriminant (Δ) using the quadratic formula, where the equation is in the form ax² + bx + c = 0.

In this case:
a = 1, b = -10, and c = -23

Δ = (-10)² - 4*1*(-23)
Δ = 100 + 92
Δ = 192

Since the discriminant (Δ) is positive, the quadratic equation has two distinct real solutions.