The ⍰ would need to be 8.
Simplified expression:
(4x^2 y^(-5))/(2^8 x^3 y)
= (4/2^8) * x^(2-3) * y^(-5-1)
= (1/8) * x^(-1) * y^(-6)
= 1/(8xy^6)
What would the ⍰ need to be in the expression below for the simplified form of the expression to be equal to
1/(8xy^6 )?
(4x^2 y^(-5))/(2^⍰ x^3 y)
1 answer