A triangle has angle measures of 75, 41 and (3x+19) solve for x

5 answers

To find the value of x in the triangle with angle measures of 75, 41, and (3x + 19), we use the fact that the sum of the angles in a triangle is always 180 degrees.

So, we add up the three angle measures and set the sum equal to 180:

75 + 41 + (3x + 19) = 180

Simplify the equation:

116 + 3x + 19 = 180
3x + 135 = 180

Now, subtract 135 from both sides:

3x = 45

Divide by 3 on both sides to solve for x:

x = 15

Therefore, x is equal to 15.
Use the triangle sum theorem to find the measures of each angle sown in the diagram (8x+5) (4x+6) (5x-1)

50, 54 and 93
46, 50 and 85
42, 44 and 79
46, 49 and 85
Let's use the fact that the sum of the angles in a triangle is always 180 degrees to solve for x and find the measures of each angle in the triangle.

Given angles: (8x + 5), (4x + 6), and (5x - 1)

Setting up the equation using the triangle sum theorem:

(8x + 5) + (4x + 6) + (5x - 1) = 180

Simplify the equation:

8x + 5 + 4x + 6 + 5x - 1 = 180
17x + 10 = 180
17x = 170
x = 10

Now that we have found x, we can substitute it back into the expressions for each angle measure:

Angle 1: 8x + 5 = 8(10) + 5 = 80 + 5 = 85
Angle 2: 4x + 6 = 4(10) + 6 = 40 + 6 = 46
Angle 3: 5x - 1 = 5(10) - 1 = 50 - 1 = 49

Therefore, the measures of the angles in the triangle are 85, 46, and 49.
so the answer is 46 49 and 85?
Yes, the correct measures of the angles in the triangle are 46, 49, and 85.