1. Gather your ys together and your 1/y^2 terms together:
1/y^2-y-2+1/y^2+y
= 0y+2/y^2-2
= 2/y^2-2
Simplify:
1/y^2-y-2+1/y^2+y
4 answers
this is not the answer that i am getting i am getting 2y-2/y(y+1)(y-2)Can you show me what is wrong or all of the work?
That is all the work.
There's a -y and a +y; they cancel out.
There are two 1/y^2 terms; they add.
There's a -2.
That's it.
Unless there are brackets you've omitted in the question?
There's a -y and a +y; they cancel out.
There are two 1/y^2 terms; they add.
There's a -2.
That's it.
Unless there are brackets you've omitted in the question?
Hm. If the question was
1/(y^2-y-2)+1/(y^2+y)
then I would get the same answer you give, but that is very different from 1/y^2-y-2+1/y^2+y
1/(y^2-y-2)+1/(y^2+y)
then I would get the same answer you give, but that is very different from 1/y^2-y-2+1/y^2+y
3 answers