well, centripetal force must be greater than weight
mg<=mv^2/r
v>=sqrt(g*r)
check that.
you swing the pail in a vertical circle of radius 0.900m.What minimum speed must you give the pail at the highest point of the circle if no water is to spill from it?
4 answers
i don't know where to go from there
v is the minimum speed.
Consider the following equation in the y-direction.
Fy=T+Fg=ma
Or in this case...
T+Fg=(mv^2)/R
Tension equals to 0 because when the pail of water is at the highest point, tension is nonexistent.
Therefore...
mg=(mv^2)/R
Cancel out mass
g=(v^2)/R
(Rg)^(1/2)=v
Plug in values.
Fy=T+Fg=ma
Or in this case...
T+Fg=(mv^2)/R
Tension equals to 0 because when the pail of water is at the highest point, tension is nonexistent.
Therefore...
mg=(mv^2)/R
Cancel out mass
g=(v^2)/R
(Rg)^(1/2)=v
Plug in values.