you swing the pail in a vertical circle of radius 0.900m.What minimum speed must you give the pail at the highest point of the circle if no water is to spill from it?

4 answers

well, centripetal force must be greater than weight

mg<=mv^2/r
v>=sqrt(g*r)
check that.
i don't know where to go from there
v is the minimum speed.
Consider the following equation in the y-direction.

Fy=T+Fg=ma

Or in this case...

T+Fg=(mv^2)/R

Tension equals to 0 because when the pail of water is at the highest point, tension is nonexistent.

Therefore...

mg=(mv^2)/R

Cancel out mass

g=(v^2)/R

(Rg)^(1/2)=v

Plug in values.