Asked by Anonymous
you swing the pail in a vertical circle of radius 0.900m.What minimum speed must you give the pail at the highest point of the circle if no water is to spill from it?
Answers
Answered by
bobpursley
well, centripetal force must be greater than weight
mg<=mv^2/r
v>=sqrt(g*r)
check that.
mg<=mv^2/r
v>=sqrt(g*r)
check that.
Answered by
Anonymous
i don't know where to go from there
Answered by
bobpursley
v is the minimum speed.
Answered by
Young J. Hong
Consider the following equation in the y-direction.
Fy=T+Fg=ma
Or in this case...
T+Fg=(mv^2)/R
Tension equals to 0 because when the pail of water is at the highest point, tension is nonexistent.
Therefore...
mg=(mv^2)/R
Cancel out mass
g=(v^2)/R
(Rg)^(1/2)=v
Plug in values.
Fy=T+Fg=ma
Or in this case...
T+Fg=(mv^2)/R
Tension equals to 0 because when the pail of water is at the highest point, tension is nonexistent.
Therefore...
mg=(mv^2)/R
Cancel out mass
g=(v^2)/R
(Rg)^(1/2)=v
Plug in values.
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