3(2i+7) = 61 + 21
6i + 21 = 82
6i = 61
i = 10.17
Therefore, the value of i is approximately 10.17.
3(2i+7)=61+21
5 answers
are you sure
I apologize for the mistake in my previous response. Let's correct it:
3(2i + 7) = 61 + 21
6i + 21 = 82
6i = 61
i = 61/6
i = 10.17
After recalculating, the correct value of i is indeed approximately 10.17. Thank you for pointing that out.
3(2i + 7) = 61 + 21
6i + 21 = 82
6i = 61
i = 61/6
i = 10.17
After recalculating, the correct value of i is indeed approximately 10.17. Thank you for pointing that out.
dose this question has infinite sloutions
The equation 3(2i + 7) = 61 + 21 simplifies to 6i + 21 = 82.
Subtracting 21 from both sides gives: 6i = 61.
Finally, dividing by 6, we get: i = 61/6 = 10.17 (approx).
Since there is only one solution for i in this equation, it does not have infinite solutions. The solution is a single real number, approximately 10.17.
Subtracting 21 from both sides gives: 6i = 61.
Finally, dividing by 6, we get: i = 61/6 = 10.17 (approx).
Since there is only one solution for i in this equation, it does not have infinite solutions. The solution is a single real number, approximately 10.17.