The Triangle Inequality Theorem states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.
Using this theorem, we can determine which option could be the third side of a triangle if the first two sides measure 4 and 6.
Option 1: 11
4 + 6 = 10 < 11
This option does not satisfy the Triangle Inequality Theorem.
Option 2: 9
4 + 6 = 10 > 9
This option satisfies the Triangle Inequality Theorem.
Option 3: 1
4 + 6 = 10 > 1
This option satisfies the Triangle Inequality Theorem.
Option 4: 2
4 + 6 = 10 = 2
This option does not satisfy the Triangle Inequality Theorem.
Therefore, the third side of the triangle could be either 9 or 1.
Apply the Triangle Inequality Theorem and determine which option could be the third side of a triangle if the first two sides measure 4 and 6.(1 point)
Responses
11
11
9
9
1
2
2
9 answers
there is only one answer
I apologize for the mistake in my previous response.
The correct answer is that the third side of the triangle could be 1.
When the first two sides measure 4 and 6, the sum of these two sides is 10, which is greater than the third side of 1.
Therefore, 1 satisfies the Triangle Inequality Theorem and could be the third side of the triangle.
The correct answer is that the third side of the triangle could be 1.
When the first two sides measure 4 and 6, the sum of these two sides is 10, which is greater than the third side of 1.
Therefore, 1 satisfies the Triangle Inequality Theorem and could be the third side of the triangle.
please give a small example
Sure! Here's an example using the Triangle Inequality Theorem:
Let's say we have a triangle with side lengths of 3, 4, and 5.
Using the Triangle Inequality Theorem, we can determine if this could be a valid triangle:
- In order to be a triangle, the sum of the lengths of any two sides must be greater than the length of the third side.
- For the sides of 3, 4, and 5:
- 3 + 4 > 5 (3 + 4 = 7 which is greater than 5)
- 4 + 5 > 3 (4 + 5 = 9 which is greater than 3)
- 3 + 5 > 4 (3 + 5 = 8 which is greater than 4)
Since all three combinations satisfy the Triangle Inequality Theorem, a triangle with side lengths of 3, 4, and 5 is valid.
Let's say we have a triangle with side lengths of 3, 4, and 5.
Using the Triangle Inequality Theorem, we can determine if this could be a valid triangle:
- In order to be a triangle, the sum of the lengths of any two sides must be greater than the length of the third side.
- For the sides of 3, 4, and 5:
- 3 + 4 > 5 (3 + 4 = 7 which is greater than 5)
- 4 + 5 > 3 (4 + 5 = 9 which is greater than 3)
- 3 + 5 > 4 (3 + 5 = 8 which is greater than 4)
Since all three combinations satisfy the Triangle Inequality Theorem, a triangle with side lengths of 3, 4, and 5 is valid.
4 and 6 are already given to you and 3 is not an answer
My apologies for not providing a clear and accurate example earlier. Let's try again using the given sides of 4 and 6.
Given the two sides are 4 and 6, we are looking for a valid third side using the Triangle Inequality Theorem.
- For a triangle to be valid, the sum of the lengths of any two sides must be greater than the length of the third side.
Let's consider the possible third side options:
1. Option: 1
- 4 + 6 > 1
- 10 > 1
- 1 satisfies the Triangle Inequality Theorem and could be a valid third side of the triangle.
Thus, when the first two sides measure 4 and 6, the third side of length 1 is valid according to the Triangle Inequality Theorem.
Given the two sides are 4 and 6, we are looking for a valid third side using the Triangle Inequality Theorem.
- For a triangle to be valid, the sum of the lengths of any two sides must be greater than the length of the third side.
Let's consider the possible third side options:
1. Option: 1
- 4 + 6 > 1
- 10 > 1
- 1 satisfies the Triangle Inequality Theorem and could be a valid third side of the triangle.
Thus, when the first two sides measure 4 and 6, the third side of length 1 is valid according to the Triangle Inequality Theorem.
good
I'm glad that explanation was helpful. If you have any more questions or need further assistance, feel free to ask!