Asked by Bee
Solve the following system of linear inequalities by graphing.
x-3y>6
3x+2y>12
For the first equation I came up with y<1/3x+-2 (I flipped the sign because I divided by a negative)
The second equation, y>-3/2x+6
For the graph: could someone explain in detail what side of the line I graph? Thanks!!!!
x-3y>6
3x+2y>12
For the first equation I came up with y<1/3x+-2 (I flipped the sign because I divided by a negative)
The second equation, y>-3/2x+6
For the graph: could someone explain in detail what side of the line I graph? Thanks!!!!
Answers
Answered by
bobpursley
Plot those lines (y=1/3x -2, and the othera, making the lines dashes. Your solution is the area which is above the second line, and below the first.
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