Asked by Anonymous

Another one.
I get real confused with all this
Multiply, Simplify if possible
3x^3/11q^3 * 121q^6/9x
the answer I got was
363q^6x^3/99q^3x
can you please show me how if it is wrong
Answered by jim
Your answer is absolutely right, but just not yet simplified.

You should see that you can divide by 3 top and bottom. That reduces the constants to 121 and 33.

Now look at the x and q terms without the constants:

x^3q^6
------
xq^3

Can you divide top and bottom by x? By q? By q again?
Answered by Anonymous
so it is
121q^3x^2/33
Answered by jim
Yes!

When you get confused because there are just too many letters and numbers, try to isolate them and look at one at a time. The secret of success is getting used to being confused. :-)
Answered by Anonymous
Thank you
Answered by jim
You're welcome.
Answered by Anonymous
I was wondering is this right by factoring here is a example of what I am learning
x^2-5x-24/x^2-6x+9 * x-3/x-8
the answer that they got was
x+3/x-3
I am so confused because there are two examples and I am not sure what is right
Answered by jim
x^2-5x-24 = (x-8)(x+3)
x^2-6x+9 = (x-3)(x-3)

Make sure you understand these two first!

Factoting x^2 + ax + b, you look for two numbers that ADD to a, but MULTIPLY to b. So in the first case, 6*4 = 24, but they don't add to 5, no matter where I put the minus. But -8 * 3 and -8 + 3 give me the answer I want.

I don't get the answer you give for the whole expression. Are the brackets in the right place?
Answered by jim
Ah. I see. I was reading it differently.

(x^2-5x-24) (x-3)
--------- * ------
(x^2-6x+9) (x-8)

= ((x-8)(x+3)(x-3))/((x-3)(x-3)(x-8))

x-8 and x-3 cancel top and bottom, and leave you with:

(x+3)/(x-3)
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