Question

hydrogen H2, molar mass = 2.016

C3H60 + H2 C3H7OH

Assuming 10.50 g of acetone and 20.50 g of hydrogen are used, answer the following questions:

Part: 0 / 6

Rubbing alcohol, or isopropanol ( C3H7OH, molar mass = 60.09

g
- according to the following balanced equation:
mol

, can be prepared by the reaction of acetone C3H6O, molar mass = 58.08 -
mol

Part 1 of 6

moles of acetone =

10

How many moles of acetone are used? Be sure your answer has the correct number of significant figures.

mol C3H6O

Answer 1

To find the moles of acetone used, we first need to convert the given mass of acetone (10.50 g) to moles using the molar mass of acetone:

10.50 g C3H6O x (1 mol C3H6O / 58.08 g C3H6O) = 0.1806 mol C3H6O

Therefore, the number of moles of acetone used is 0.1806 mol.