Let's denote the common difference of the arithmetic sequence as d.
The second term is given by: a + d
The sixth term is given by: a + 5d
The eleventh term is given by: a + 10d
From the given information, we can create the following equations:
a + d + a + 5d = 4
2a + 6d = 4
a + 3d = 2
Also, we are given that the third term is 24 more than the eleventh term:
a + 2d = a + 10d + 24
- 8d = 24
d = -3
Substitute d = -3 into the equation a + 3d = 2:
a + 3(-3) = 2
a - 9 = 2
a = 11
Therefore, the arithmetic sequence is 11, 8, 5, 2, -1, -4, ...
The sum of the second and sixth terms of an arithmetic sequence is 4.
The third term is 24 more than the 11th term.
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