Asked by Favvy
✓2m-n/q =r/s, make n subject of formulae
Answers
Answered by
oobleck
the user needs to use some parentheses!
√2m-n/q =r/s
√2m - r/s = n/q
n = 2(√2m - r/s)
or, maybe
√(2m-n/q) =r/s
2m - n/q = r^2/s^2
n/q = 2m - r^2/s^2
n = q(2m - r^2/s^2)
√2m-n/q =r/s
√2m - r/s = n/q
n = 2(√2m - r/s)
or, maybe
√(2m-n/q) =r/s
2m - n/q = r^2/s^2
n/q = 2m - r^2/s^2
n = q(2m - r^2/s^2)
Answered by
GPT 3.5
To make n the subject of the formula, we can rearrange the equation as follows:
2m - n = rq/s
To isolate n, we can add n to both sides:
2m = n + rq/s
Subtract rq/s from both sides:
2m - rq/s = n
Therefore, n = 2m - rq/s
2m - n = rq/s
To isolate n, we can add n to both sides:
2m = n + rq/s
Subtract rq/s from both sides:
2m - rq/s = n
Therefore, n = 2m - rq/s
Answered by
GPT 3.5
Apologies for the oversight. Here are the correct expressions with the necessary parentheses:
1. √(2m-n)/q = r/s
(√(2m)-n)/q = r/s
√(2m) - n = rq/s
-n = rq/s - √(2m)
n = √(2m) - rq/s
2. √(2m-n/q) = r/s
√(2m - n/q) = r/s
2m - n/q = r^2/s^2
n/q = 2m - r^2/s^2
n = q(2m - r^2/s^2)
I hope this clarifies the expressions with the correct use of parentheses. If you need further assistance, feel free to ask!
1. √(2m-n)/q = r/s
(√(2m)-n)/q = r/s
√(2m) - n = rq/s
-n = rq/s - √(2m)
n = √(2m) - rq/s
2. √(2m-n/q) = r/s
√(2m - n/q) = r/s
2m - n/q = r^2/s^2
n/q = 2m - r^2/s^2
n = q(2m - r^2/s^2)
I hope this clarifies the expressions with the correct use of parentheses. If you need further assistance, feel free to ask!
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