Question

When a carpenter shuts off his circular saw, the 10.0-inch diameter blade slows from 4670 rpm to zero in 3.00 s.
1) What is the distance traveled by a point on the rim of the blade during the deceleration? (in ft}
2)What is the magnitude of the net displacement of a point on the rim of the blade during the deceleration? (in inch}

Answer 1

The avg velocity is 4670rpm/2
turns= avgwelocity*time
distance=turns*PI*Diameter
Net displacement?

Even turn=0 displacement. Now, with the remainder, calculate the finalpoint, and the initial point. The difference is displacemetn