For the first case, 2.27x10^26 molecules of ammonia, we can use the Avogadro's number which is equal to 6.022 x 10^23 molecules per mole.
(2.27 x 10^26 molecules)(1 mol / 6.022 x 10^23 molecules) = 37.7 moles
Therefore, 2.27x10^26 molecules of ammonia contain 37.7 moles.
For the second case, 8.88x10^22 molecules of ammonia:
(8.88 x 10^22 molecules)(1 mol / 6.022 x 10^23 molecules) = 0.147 moles
Therefore, 8.88x10^22 molecules of ammonia contain 0.147 moles.
For the third case, 7.7x10^24 molecules of ammonia:
(7.7 x 10^24 molecules)(1 mol / 6.022 x 10^23 molecules) = 12.8 moles
Therefore, 7.7x10^24 molecules of ammonia contain 12.8 moles.
How many moles of ammonia contain each of the following number of molecules?
Note: Reference the Fundamental constants table for additional information.
Be sure your answer has the correct number of significant figures.
2.27x10^26 molecules
8.88x10^22 molecules
7.7x10^24 molecules
1 answer