(a) Null hypothesis (H0): The mean tuition rates for the various regions are equal.
Alternate hypothesis (Ha): There is a difference in the mean tuition rates for the various regions.
(b) Decision rule:
Reject the null hypothesis if the calculated F-statistic is greater than the critical F-value for a significance level of 0.05.
(c) ANOVA table:
Source of Variation | SS | df | MS | F
Between groups | 19.67 | 2 | 9.84 |
Within groups | 26.57 | 13 | 2.04 |
Total | 46.24 | 15 |
(d) The F-statistic is calculated by dividing the mean square between groups by the mean square within groups: 9.84/2.04 = 4.82
(e) Compare the F-statistic (4.82) to the critical F-value for a significance level of 0.05 with degrees of freedom 2 and 13. If the calculated F-statistic is greater than the critical F-value, reject the null hypothesis. If it is less than the critical F-value, fail to reject the null hypothesis.