To calculate the volume occupied by 32.0g of oxygen at STP, we first need to find the number of moles of oxygen using its molar mass.
Molar mass of oxygen (O2) = 32.0 g/mol
Number of moles of oxygen = 32.0g / 32.0g/mol = 1 mol
Since 1 mole of any gas occupies 22.4 dm³ at STP, 32.0g of oxygen will also occupy 22.4 dm³ at STP.
Similarly, for 44.0g of carbon dioxide (CO2):
Molar mass of carbon dioxide (CO2) = 44.0 g/mol
Number of moles of carbon dioxide = 44.0g / 44.0g/mol = 1 mol
Therefore, 44.0g of carbon dioxide will also occupy 22.4 dm³ at STP.
32.0g of oxygen and 44.0g of carbon dioxide each occupies 22.4dm3 at s.t.p
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