Which expression is equivalent to 40x^-3y^5/8x^-2y^-2 for all values for x and y where the expression is defined?

A. 5xy^7
B. 5x^5y^7
C. 5/xy^7
D. 5y^7/x

1 answer

To simplify the expression, we can combine the like terms in the numerator and the denominator.

In the numerator, we have 40x^(-3)y^5, which can be rewritten as (40/x^3)y^5.

In the denominator, we have 8x^(-2)y^(-2), which can be rewritten as (8/x^2)(1/y^2).

Now we can rewrite the expression as (40/x^3)y^5 / (8/x^2)(1/y^2).

Next, we can simplify the expression by canceling out common factors between the numerator and the denominator.

Canceling out the x^2 and x^3 terms in the numerator and the denominator, we get:
40y^5 / 8 * 1/y^2.

Simplifying further, we have:
40y^5 / (8/y^2) = 40y^5 * y^2 / 8.

Multiplying the terms, we get:
(40 * y^5 * y^2) / 8 = (40 * y^(5+2)) / 8 = (40 * y^7) / 8.

Finally, we can simplify the expression by dividing 40 and 8:
(40 * y^7) / 8 = 5y^7.

Therefore, the expression is equivalent to 5y^7.

Answer: \boxed{A) 5xy^7}.
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